28x^2+148x+24=0

Solution for 28x^2+148x+24=0 equation:

28x^2+148x+24=0

a = 28; b = 148; c = +24;
Δ = b2-4ac
Δ = 1482-4·28·24
Δ = 19216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19216}=\sqrt{16*1201}=\sqrt{16}*\sqrt{1201}=4\sqrt{1201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(148)-4\sqrt{1201}}{2*28}=\frac{-148-4\sqrt{1201}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(148)+4\sqrt{1201}}{2*28}=\frac{-148+4\sqrt{1201}}{56}
$